x→∞ lim(3x+sinx)/(2x-sinx)=

lim（x→∞）（3x+sinx）/(2x-sinx)的极限 x→∞ lim(3x+sinx)/(2x-sinx)= lim(x→∞)[(x＋sinx)/(x-sinx)]＝? lim[x→∞]【(x+1)sinx】/(2x^3-3x+2) 1.lim x->∞ （2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 （e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim (x→0)x-sinx/x lim x→0 sin2x/sin5xlim x→0 (1-cos2x)/x²lim x→0 in(1-x/2)^1/xlim x→∞ (1+2/x)^2x+1lim x→0 sin2x/sin5xlim x→0 (1-cos2x)/x²lim x→0 in(1-x/2)^1/xlim x→∞ (1+2/x)^2x+1lim x→3 (x-3)cos1/(x-3)lim x→0 (e^sinx-e^x)/(sinx-x) lim (x->0) 3x/(sinx-x) 求lim(x趋于∞）(2x+sinx)/(3x-sinx) 求下列极限,lim(x+2sinx)/(x+3sinx),x→0烦请给出具体步骤, 1.lim(2x-sinx)/(2x+sinx) (x→0)2.lim(sinsinx)/x (x→0)3.lim 4/y (y→∞) 计算极限① lim(x→+∞) 1 / [ (√x^2+3x) - x ],② lim(x→1) (sinx-sin1)/(x-1) lim(x→∞)(x-sinx)/x=? x→∞ lim(cosx+x)/(sinx-x) 求极限? x→∞ lim （x+sinx）/x=?rt x→∞ lim （x+sinx）/x=?rt lim√x(sinx+cosx)/x+1 x→+∞ lim(x→∞) (xsin(1/x)+1/x(sinx))