若4x^2+8xy+4y^2+4y-3=0,求x+y的值

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若4x^2+8xy+4y^2+4y-3=0,求x+y的值若4x^2+8xy+4y^2+4y-3=0,求x+y的值若4x^2+8xy+4y^2+4y-3=0,求x+y的值4x^2+8xy+4y^2+4x

若4x^2+8xy+4y^2+4y-3=0,求x+y的值
若4x^2+8xy+4y^2+4y-3=0,求x+y的值

若4x^2+8xy+4y^2+4y-3=0,求x+y的值
4x^2+8xy+4y^2+4x+4y-3
=4(x+y)^2+4(x+y)-3
=[2(x+y)-1][2(x+y)+3]
=0
2(x+y)-1=0或2(x+y)+3=0
x+y=1/2或x+y=-3/2

4x^2+8xy+4y^2+4y-3=0----->4(x^2+2xy+y^2)+4y-3=0------>4(x+y)^2+4y-3=0----->(x+y)^2=3/4-y---->只要能保证3/4-y≥0即可------>y≤3/4即可。随便找个符合此条件的y，3/4-y范围可以是全体正数，而x+y只需要将这个数开方一次即可，所以x+y可以是任意正数。

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