y=ln(1+2x) 则dy=急,谢谢.

y=ln(1+2x) 则dy=急,谢谢. 设y=ln(1+x^2)则dy= 急需!急需!函数y=ln（1+x平方）,则dy=?谢谢! y=ln(2x+5),则dy= y=xarcsinx+ln 根号(1-x^2) 求dy y=cos2x+ln(1-2x)+cos1 求dy y=ln(x^2+1),求dy y=ln(2√x-1) 求dy 已知函数y=ln[x+(1+x^2)^(1/2)],则dx/dy dy/dx 求导（急急急）找一下错误指出,X=a ln{(a+√（a^2-y^2))/Y}X=a(ln a +1/2 ln(a^2-y^2)- ln Y)这里微分 把a移到左边,1/a=(1/2)*1/（a^2-y^2)*(-2y)*dy/dx -(1/y)*(dy/dx )1/a=-{y/(a^2-y^2)} dy/dx- (1/y ) (dy/dx)能给找出错误 y=ln(x^2-x+2) 求dy 设y=ln(x/1+x)-cot2x,求dy. y=1/x+ln根x.求dy y=ln(x+x^2) 求dy 设y=ln[cos(1+3x^2)],则dy= 已知y=ln²x,则dy=? 设y=ln(x)则dy=?gfng y=5+ ln x ,则dy=多少