y=ln(x^2+1),求dy
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y=ln(x^2+1),求dyy=ln(x^2+1),求dyy=ln(x^2+1),求dydy=1/(x²+1)d(x²+1)=2xdx/(x²+1)
y=ln(x^2+1),求dy
y=ln(x^2+1),求dy
y=ln(x^2+1),求dy
dy=1/(x²+1) d(x²+1)
=2xdx/(x²+1)
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