若12X^2+12Y^2=25XY,试求X/Y的值

来源：学生作业帮助网编辑：六六作业网时间：2024/11/17 05:47:19

若12X^2+12Y^2=25XY,试求X/Y的值若12X^2+12Y^2=25XY,试求X/Y的值若12X^2+12Y^2=25XY,试求X/Y的值12X^2+12Y^2=25XY即：12x^2-2

若12X^2+12Y^2=25XY,试求X/Y的值
若12X^2+12Y^2=25XY,试求X/Y的值

若12X^2+12Y^2=25XY,试求X/Y的值
12X^2+12Y^2=25XY
即：12x^2-25xy+12y^2=0
十字相乘分解因式得：(4x-3y)(3x-4y)=0
所以4x-3y=0或3x-4y=0
即x/y=3/4或x/y=4/3

两边同时除以y^2就可以了然后解个一元二次方程就可以了~~~

两边同除以12*y*y
令x/y=a
a*a+1=25/12a
a=(25/12+7/12)/2=8/3,
a=(25/12-7/12)/2=3/4

12/13

12x^2+12y^2=25xy
(12x^2+12y^2)/y^2=25xy/y^2
12(x/y)^2-25(x/y)+12=0
(x/y)=[25±√(25^2-4*12*12)]/(2*12)
=(25±7)/24
(x/y)=(4/3),(3/4)

若12X^2+12Y^2=25XY,试求X/Y的值已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y 若x+y=4,x^3+y^3=(x+y)(x^2-xy+y^2)z,求x^3+12xy+y^3的值. x^2+xy=12,xy+y^2=15,求(x+y)^2-(x+y)(x-y) 若x+y=12,xy=9,求(x^2+3xy+2y^2)÷(x^2y+2xy^2)的值已知x+y=12,xy=9,试求X的平方+3XY+2Y的平方/x的平方Y+2XY的平方 x^2-7xy+12y^2=0,求x^2-2xy+y^2/2xy的值已知x²-7xy+12y²=0求x²-xy+y²/2xy的值若x^2+xy+y=14,y^2+xy+x=28,求x+y 若12x²-25XY=-12Y²,试求Y/X的值若12x²-25xy=-12y²,试求x:y的值已知X+Y=3,XY=-1,求2(X-Y)^4-9(X-Y)^2+12XY 已知x2+xy=12,xy+y2=15,求(x+y)2-(x+y)(x-y)的值若（x-y)^2=12,(x+y)^2=16,求xy的值若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思，是3x-2xy-3y/x-2xy-y x-y=4xy,试求2x+3xy-2y/x-2xy-y x-y=4xy,试求2x+3xy-2y/x-2xy-y 若(y-x)/xy=3,求分式(2x+3xy-2y)/(x-2xy-y)的值