满足an+1=an+3n+2,且a1=2,求an

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满足an+1=an+3n+2,且a1=2,求an满足an+1=an+3n+2,且a1=2,求an满足an+1=an+3n+2,且a1=2,求anan-an-1=3(n-1)+2an-1-an-2=3(

满足an+1=an+3n+2,且a1=2,求an
满足an+1=an+3n+2,且a1=2,求an

满足an+1=an+3n+2,且a1=2,求an
an-an-1= 3(n-1)+2
an-1-an-2= 3(n-2)+2
...
a2-a1= 3+2
把以上式子相加 得
an-a1= 3(1+2+3+...+n-1)+2(n-1)
=3/2 * n(n-1) +2(n-1)
=>an=3/2 * n(n-1) +2(n-1) +2
=3/2 * n(n-1) +2n

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