设log2(5)=x,log5(3)=y,试用x,y表示log24(20)
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设log2(5)=x,log5(3)=y,试用x,y表示log24(20)设log2(5)=x,log5(3)=y,试用x,y表示log24(20)设log2(5)=x,log5(3)=y,试用x,y
设log2(5)=x,log5(3)=y,试用x,y表示log24(20)
设log2(5)=x,log5(3)=y,试用x,y表示log24(20)
设log2(5)=x,log5(3)=y,试用x,y表示log24(20)
x=log2(5)=lg5/lg2
y=log5(3)=lg3/lg5
log24(20)=lg(20)/lg(24)=lg(4×5)/lg(8×3)=(lg4+lg5)/(lg8+lg3)
=(2lg2+lg5)/(3lg2+lg3)
=(2 +lg5/lg2)/(3 +lg3/lg2)
=(2+lg5/lg2)/[3+(lg3/lg5)(lg5/lg2)]
=(x+2)/(xy+3)
lg5/lg2=x,lg2=lg5/x
lg3/lg5=y,lg3=ylg5
log24(20)=lg20/lg24=[2lg2+lg5]/[3lg2+lg3]=[2lg5/x+lg5]/[3lg5/x+ylg5]=[2/x+1]/[3/x+y]=(2+x)/(3+xy)
比较麻烦,从新学习了以前的知识才解出来。给你个答案吧
(x+2)/(xy+3)
设log2(5)=x,log5(3)=y,试用x,y表示log24(20)
(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
log2(log5 x)=-1
若(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y) 则 A.x+y>0 B.x+y=0 D.
log2(5) ×log5(8)=3步骤
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