fx=cos^4x+2sinxcosx-sin^4x求fx的最小正周期

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fx=cos^4x+2sinxcosx-sin^4x求fx的最小正周期fx=cos^4x+2sinxcosx-sin^4x求fx的最小正周期fx=cos^4x+2sinxcosx-sin^4x求fx的

fx=cos^4x+2sinxcosx-sin^4x求fx的最小正周期
fx=cos^4x+2sinxcosx-sin^4x求fx的最小正周期

fx=cos^4x+2sinxcosx-sin^4x求fx的最小正周期
fx=cos^4x+2sinxcosx-sin^4x
=(cos²x+sin²x)(cosx²-sin²x)+sin2x
=1×cos2x+sn2x;
=√2(cos2x×(√2/2)+sin2x×(√2/2))
=√2sin(2x+π/4);
最小正周期T=2π/2=π;