log2(12)-log4(9)的值是
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log2(12)-log4(9)的值是log2(12)-log4(9)的值是log2(12)-log4(9)的值是log2(12)-log4(9)=log2(4*3)-log2(3)=log2(4)+
log2(12)-log4(9)的值是
log2(12)-log4(9)的值是
log2(12)-log4(9)的值是
log2(12)-log4(9)
=log2(4*3)-log2(3)
=log2(4)+log2(3)-log2(3)
=2log2(2)
=2
log2(12)-log4(9)的值是
算式log2^12-log4^9的值
log2的12-log4的9 的值是多少?
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log2 20-log4 25的答案是
[log2(3)+log4(9)][log3(4)+log9(2)]等于注意:log2的2是下标,后同
log2^x=log4^9
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方程log2(x+1)^2+log4(x+1)=5的解是
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化简:(log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)