求∫(0→π)√sinx-sin^3 x dx

求∫(0→π)√sinx-sin^3 x dx 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 sinx>sin(2π/3-x)（0 ∫（0,π/2）sinx/(3+sin^2x)dx求定积分 limx→+0+ (tan9x)^3/2*sin√x/sinx^2 利用等价无穷小求极限 求极限(x趋向于0时）lim[sinx-sin(sinx)]/(sinx)^3 求X解集：sinx=2sin(π/3-x) 求极限lim(x-->0) (tanX-sinX)/[(sin^3)X] limx→0[sinx-sin(sinx)]sinx/x^4 求y=sin(x-π/3)sinx最大值 3/5=sin(x+π/4) 求sinx 求 (tanx-sinx)/(sin^3 x) 当x→0时的极限 极限limx趋近于0 (sin(sinx)-sinx)/x^3怎么求? 已知2sin平方x-3sinxcosx+cos平方=0 求(cosx-sinx)/(cosx+sinx) lim(1+sinx-sin(sinx))^x^-3 x趋于0 求定积分（0到π／2）sin^3x／（sinx+cosx）dx=? 求极限lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0 已知函数f(x)=2√3sin(x/2)cos(x/2)-(cos²x/2-sin²x/2)⑴求函数f(x)的单调递增区间；⑵若f(x)=0,求（sinx+cos(π+x）/（sinx+sin(π/2-x）的值