求dy/dx=(x-y+5)/(x+y-2)
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求dy/dx=(x-y+5)/(x+y-2)求dy/dx=(x-y+5)/(x+y-2)求dy/dx=(x-y+5)/(x+y-2)dy/dx=(x-y+5)/(x+y-2)=[(x+3/2)-(y-
求dy/dx=(x-y+5)/(x+y-2)
求dy/dx=(x-y+5)/(x+y-2)
求dy/dx=(x-y+5)/(x+y-2)
dy/dx=(x-y+5)/(x+y-2)=[(x+3/2)-(y-7/2)]/[(x+3/2)+(y-7/2)]
令 v=y-7/2,u=x+3/2,原方程化为 dv/du=(u-v)/(u+v) 变为齐次方程.
再令 p=v/u,方程化为 p+udp/du=(1-p)/(1+p),
则化成可分离变量型 (1+p)dp/(1-2p-p^2)=du/u.
下面运算自己可以计算了.
求dy/dx=(x-y+5)/(x+y-2)
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