x^y-y^x=2,求dy/dx
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 12:09:43
x^y-y^x=2,求dy/dxx^y-y^x=2,求dy/dxx^y-y^x=2,求dy/dx令x^y=u,则:ylnx=lnu,∴lnxdy/dx+y/x=(1/u)du/dx,∴u(lnxdy/
x^y-y^x=2,求dy/dx
x^y-y^x=2,求dy/dx
x^y-y^x=2,求dy/dx
令x^y=u,则:ylnx=lnu,∴lnxdy/dx+y/x=(1/u)du/dx,∴u(lnxdy/dx+y/x)=du/dx,
∴du/dx=x^y·lnx·dy/dx+(y/x)x^y.
令y^x=t,则:xlny=lnt,∴lny+(x/y)dy/dx=(1/t)dt/dx,∴t[lny+(x/y)dy/dx]=dt/dx,
∴dt/dx=y^x·lny+(x/y)y^x·dy/dx.
∵x^y+y^x=2,∴u+t=2,∴du/dx+dt/dx=0,
∴[x^y·lnx·dy/dx+(y/x)x^y]+[y^x·lny+(x/y)y^x·dy/dx]=0,
∴[x^y·lnx+(x/y)y^x]dy/dx=-[(y/x)x^y+y^x·lny],
∴dy/dx=-[(y/x)x^y+y^x·lny]/[x^y·lnx+(x/y)y^x].
x^y-y^x=2,求dy/dx
求dy/dx=(x-y+5)/(x+y-2)
x^2+y^2=e^y求dy/dx
求dy/dx=x/y+(cosx/y)^2通解
已知x=y^2-4y,求dy/dx
(x^2)dy+(y^2)dx=dx-dy
(dy/dx)-y=x求微分方程
y=(sinx)^x 求DY/DX
y=x+lnx,求dx/dy
求dy/dx= - x/y
y=2x^2+x求dy/dx
x=sin(y/x)+e^2 求dy/dx
y=e^x/x^2+sin2x 求dy/dx
dy/dx=x+y
(x+y)dy+(x-y)dx=0求通解
设 x/y=ln(y/x) ,求 dy/dx
dy/dx=(x+y)/(x-y)求通解
求微分方程 x*dy/dx=y*ln(y/x) .