y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx

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y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dxy=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dxy=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dxx^2+

y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx

y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
x^2+3y^4+x+2y=1 两边同时对x求导,得到:
2x+3*4*y^3*dy/dx+1+2*dy/dx=0
(12y^3+2)dy/dx=-1-2x
dy/dx=-(1+2x)/(2+12y^3)