求sin²1°＋sin²2°＋...＋sin²89°的值

求sin²1°＋sin²2°＋...＋sin²89°的值 求sin²1°+sin²2°+sin²3°……sin²89°=? sin²1°+sin²2°+sin²3°+.+sin²89 初三数学（三角函数1）1、求sin²1°+sin²2°+sin²3°+……+sin²89°的值. sin²1°+sin²2°+sin²3°+...+sin²88°+sin²89°+sin²90°=等于多少? 已知α为锐角,满足sin²α＋cos²α＝1,sinα=（90º-α）,根据上述结论解答下列问题（1）求sin²36º+sin²54º的值（2）求sin²1º+sin²2º+sin²3º+····+sin²88&ord sin²1°+sin²2°+sin²3°+.+sin²89°= -1为什么? sin²1°+sin²2°+…+sin²88°+sin²89°= sin²1°+sin²2°+……+sin²88°+sin²89°=? sin²1°+sin²2°+sin²3°.+sin²89°= 求sin²1º+sin²2º+sin²3º+……+sin²88º+sin²89º. 计算sin²1°+sin²2°+……+sin²89° 三角函数的证明题的这一步是怎么推出来的求证 sin（A+B）sin（A-B）/sin²Acos²B =1- tan²B/tan²A证明：左边 =（sinAcosB+cosAsinB）（sinAcosB-cosAsinB）/sin²Acos²B = sin²Acos&sup sin²1°+sin²2°+sin²3°+...+sin²88°+sin²89°= △ABC中,若（sin²B+sin²C-sin²A）/sinBsinC = 1求角A sin²1º＋sin²2º＋sin²3º＋...＋sin²88º的值等于 sin²1°+sin²2°+sin²3°+…+sin²89°=?麻烦写下过程, 已知Sin10°=α,求3/Sin²40°-1/Cos²40°