函数f(x)=sin(2x-4/兀)-2√2sin²x的最小正周期是

设函数f(x)=sin(2x+∮)(-兀 函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 函数f(x)=sin(2x-4/兀)-2√2sin²x的最小正周期是 已知函数f(x)=cos(x-3/ 兀)-sin(2/兀-x).(1)求函数f(x)的最小值. 函数f(x)=sin(2x-兀/4)的最小正周期是多少 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 已知函数F(X)=SIN(2X+φ)(-π 函数f(x)=sin(2x+φ)((|φ| 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+φ)(0