3x+5/(x+2)(x+3)=A/(x+2)+(x=3),求(3A+B)的2008次方A、B为常数
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3x+5/(x+2)(x+3)=A/(x+2)+(x=3),求(3A+B)的2008次方A、B为常数3x+5/(x+2)(x+3)=A/(x+2)+(x=3),求(3A+B)的2008次方A、B为常数
3x+5/(x+2)(x+3)=A/(x+2)+(x=3),求(3A+B)的2008次方A、B为常数
3x+5/(x+2)(x+3)=A/(x+2)+(x=3),求(3A+B)的2008次方
A、B为常数
3x+5/(x+2)(x+3)=A/(x+2)+(x=3),求(3A+B)的2008次方A、B为常数
A/(x+2)+B/(x+3)
=[A(x+3)+B(x+2)]/(x+2)(x+3)
=[(A+B)x+(3A+2B)]/(x+2)(x+3)
=(3x+5)/(x+2)(x+3)
所以A+B=3
3A+2B=5
所以A=-1,B=4
3A+B=1
所以(3A+B)的2008次方=1
3x+5/(x+2)(x+3)=A/(x+2)+B/x+3=(Ax+3A+BX+2B)/(x+2)(x+3)
(A+B)=3
3A+2B=5
A=-1
B=4
(3A+B)的2008次方
=(-3+4)的2008次方
=1
你把题目写清楚了吧!
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