复数数列{an}满足a1=0,an=(an-1)^2+i(n大于等于2),则它的前2007项的和为?
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复数数列{an}满足a1=0,an=(an-1)^2+i(n大于等于2),则它的前2007项的和为?复数数列{an}满足a1=0,an=(an-1)^2+i(n大于等于2),则它的前2007项的和为?
复数数列{an}满足a1=0,an=(an-1)^2+i(n大于等于2),则它的前2007项的和为?
复数数列{an}满足a1=0,an=(an-1)^2+i(n大于等于2),则它的前2007项的和为?
复数数列{an}满足a1=0,an=(an-1)^2+i(n大于等于2),则它的前2007项的和为?
周期数列:a1=0 a2=i a3=i-1 a4=-i a5=i-1 a6=-i.看出规律没,后面所有项是i-1和-i的交替.所以2007项和为2i-1003.怎么不是常数,可能是你抄错题或者我算错了.反正方法是多写几项,找周期
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