[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程

来源：学生作业帮助网编辑：六六作业网时间：2024/11/16 11:52:30

[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程12x+

[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程
[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程

[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程
12x+6y=12z+4x=12y+3z
分成两个等式:
x+y/2 = y+z/4
=>4x+2y= 4y+z
=>4x=2y+z(一）
x+y/2=z+x/3
=>6x+3y = 6z +2x
=>4x = 6z-3y(二）
结合（一）（二）
6z-3y = 2y+z
5z = 5y
z = y
代入（二）
4x = y ×6 - 3y
4x = 3y
x = 3/4y
3/4 y + y + y = 27
3y + 4y + 4y = 108
11y = 108
y = 108/11
z = 108/11
x = 81/11

我会，没有分谁帮你答啊

解,将第一个等式分解成两个等式得
x+y/2=z+x/3```````1
z+x/3=y+z/4```````2
x+y+z=27``````````3
由1得:3y=4z-x`````4
由2得:3y=4x+z`````5
3*3得:3y=81-3x-3z`6
由4,5得:4z-x=4x+z
3z=5x
由5,6得4z-x=...

全部展开

收起

先通分,12x+6y=12z+4x=12y+3z
即4x+3y-6z=0
4x-12y+9z=0
4x-2y-z=0
化简得y=z
由4x-3y=0和x+2y=27得
x=81/11,y=z=108/11

先通分。6x+6y=4z+4x =3y+3z
2x+6y-4z=0
x+3y-2z=0 因为x+y+z=27
所以3z-2y=0

x+y/2=z+x/3=y+z/4 x+y+z=27 x+2y=3x+2z=4y+z 求x:y:z 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 2x+z=10 x+y-z=4 3x-y-z=0 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 证明：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 (x+y-z)(x-y+z)= x/2=y/3=z/5 x+3y-z/x-3y+z 若x+y+z=3y=2z,则x/x+y+z=? 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 x/2=y/3=z/4,则x+2y-z/z=? (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x+y=5 2x+3y-z=9 x-y+z=4 {2x+y=10 {x-y+z=4 {3x-y-z=0