求sin100°+tan240°*cos100°的值
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求sin100°+tan240°*cos100°的值求sin100°+tan240°*cos100°的值求sin100°+tan240°*cos100°的值sin100°+tan240°*cos100
求sin100°+tan240°*cos100°的值
求sin100°+tan240°*cos100°的值
求sin100°+tan240°*cos100°的值
sin100°+ tan240°*cos100° = sin100° + tan60°*cos100° = sin100° + sqrt(3) * cos100° = 2 [0.5 *sin100° + sqrt(3) / 2 * cos100°] = 2 * sin(100 + 60) = 2 * sin(160).The end
求sin100°+tan240°*cos100°的值
求sin100°+tan240°*cos100°的值
求sec100°+tan240°*csc100°的值
sin600°+tan240°等于
sin100°cos 110° +cos100°sin110°
sin100°cos 110° cos100°sin110°
sin300°+tan240°的值是
计算:tan240°*cos240°-4sin(-210°)*cos570°求详细解题过程
化简:根号(1-2sin100°cos280°)/{cos370°-根号[1-cos^2(170°)]}
求值Sin100°sin(-160°)+cos200°cos(-280°)
求下列各三角函数值(1)tan240° (2)sin 3分之16π(3)sin(-6分之35π) (4)cos (-3分之25π)(5)tan (-4分之33π) (6)cos (-4分之45π)
化简sin100°sin﹙﹣160°﹚+cos160°cos﹙﹣280°﹚
谁帮我解下一道数学题 sin100°sin(-160°)+cos200°cos(-280)=_____
sin100°=sin80°为什么
sin100°*cos240°如何化简
sin100°=?拜托了各位 谢谢
cos225°+tan240°+sin(-60°)+tan(-420°)=
cos225°+tan240°+sin420°我没分了请见谅,明天要交呀!