若sin(π/4-α)=5/13,且α∈(0,π/2),则cos2α/cos(π/4+α)的值为

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 23:42:28
若sin(π/4-α)=5/13,且α∈(0,π/2),则cos2α/cos(π/4+α)的值为若sin(π/4-α)=5/13,且α∈(0,π/2),则cos2α/cos(π/4+α)的值为若sin

若sin(π/4-α)=5/13,且α∈(0,π/2),则cos2α/cos(π/4+α)的值为
若sin(π/4-α)=5/13,且α∈(0,π/2),则cos2α/cos(π/4+α)的值为

若sin(π/4-α)=5/13,且α∈(0,π/2),则cos2α/cos(π/4+α)的值为
cos(pai/4+α)=sin(π/4-α)=5/13,cos2α=sin2(π/4-α)=2sin(π/4-α)cos(π/4-α)=2*5/13*12/13=120/169 ,故待求式=(120/169)/(5/13)=24/13