如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=
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如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=如果实数x,y满足2x^2-6xy+9y^2-4x+4=
如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=
如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=
如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=
因为2x^2-6xy+9y^2-4x+4=0
所以x^2-4x+4+x^2-6xy+9y^2=0
(x-2)^2+(x-3y)^2=0
所以x-2=0,x-3y=0
所以y=2/3
√y=√6/3
2x^2-6xy+9y^2-4x+4=0
<=>
(x^2-4x+4)+(x^2-6xy+9x^2)=0
<=>
(x-2)^2+(x-3y)^2=0
<=>
x=2 x=3y
<=>
答案就出来了^_^
祝你好运!
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