当实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x平方y+xy平方=多少
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当实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x平方y+xy平方=多少当实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x平方y+xy平方=多少当实数x,y满足xy+x
当实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x平方y+xy平方=多少
当实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x平方y+xy平方=多少
当实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x平方y+xy平方=多少
x^2y+xy^2=xy*(x+y)
因为x+y=-(7+xy)
又x+y=(9+2xy)\3
所以(9+2xy)/3=-(7+xy)
3+2xy/3=-7-xy
5xy/3=-10
解得 xy=-6
所以x+y=-(7+xy)=-1
所以x^2y+xy^2=xy*(x+y)=-6*(-1)=6
令a=xy,b=x+y
则a+b+7=0
3b=9+2a
所以a=-6,b=-1
所以原式=xy(x+y)
=ab
=6
xy+x+y+7=0,
3x+3y=9+2xy
解得x+y=-1,xy=-6
x²y+xy²
=xy(x+y)
=-6×(-1)
=6
设xy=m
x+y=n
m+n=-7
2m-3n=-9
解得:
m=-6
n=-1
x²y+xy²
=xy(x+y)
=m*n
=(-6)*(-1)
=6
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