y= 625/256 x+ 369/64 x、y均为整数,x>6,求x、y

y= 625/256 x+ 369/64 x、y均为整数,x>6,求x、y Y=625/256X+369/64 X大于6 请问X与Y同时取整怎么解? y = （256x -369）/625,xy都必须是正整数,请问x最小是多少? x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 化简 x / y(x+y) - y / x(x+y) = x=(256y-369)/652,x、y为整数.用C语言求y的最小值 x(x+y)(x-y)-y(y+x)(y-x)=(x-y)( )填空 解方程.100/(X+Y)+64/(X-Y)=9;80/(X+Y)+80/(X-Y)=9 x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=? x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=? y=x(x (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z x+x+x+x+y+y+y=56 x+x+x+y+y=6.4 y+y+y+x+x=7.1 怎么算? 二元函数f(x,y)=x+y/x-y,求f(y/x,x/y) x-y/x+y=(x-y)²/x²-y²（x≠y) （x+y-5)*（x+y-5)+（x-y+3)=0 x*x-y*y 已知:3x-5y=0,求x/y,x-y/y,x-y/x