X3－X2－2x＝0求解

X3－X2－2x＝0求解 如果x3－x2＋x－2＝0,则x^4＋2x3－2x2＋x－1＝_____ x3－x2-2x=0求详解 xxxx求解x3-6x2+11x-6=0 X4-2X3-3X2+2X+1=0求解 2X3-4X2-3X+1=0用二分法求解 解方程X3－4X2＋2X＋6＝0 求解非齐次线性方程组x1+x2+x3=3,x2-x3=0,-x1-x2+2x3=0,2x1-x2+x3=2 设函数f (x)＝x3－4x＋a,0＜a＜2．若f (x)的三个零点为x1,x2,x3,且x1＜x2＜x3,则 （）A．x1＞－1 B．x2＜0 C．x2＞0 D．x3＞2 应该选哪一个?具体思路 因式分解（1+x+x2+x3)2-x3 一元三次方程求解x3（3为上标）-100x2（2为上标）-29584x+2958400=0 求解齐次线性方程组...X1+X2+2X3-X4=0{ 2X1+X2+X3-X4=02X1+2X2+X3+2X4=0 用克莱姆法则求解,急X1+X2+X3=6X1+2X2+3X3=14X1+X2-X3=0 x2-x-1=0,-x3+2x2+2008= 线性方程组求解,x1+2x2+x3-x4=1 3x1+6x2-x3-3x4=0 mathematica如何求解含有三角函数的方程?FindRoot[{3 x1^3 + 2 x2 - 5 + Sin[x1 - x2] Sin[x1 + x2] == 0,-x1*Exp[x1 - x2] + x2 (4 + 3 x2^2) + 2 x3 + Sin[x2 - x3] Sin[x2 + x3] - 8 == 0,-x2*Exp[x2 - x3] + 4 x3 - 3 ==0},{x1,Pi/2},{x2,2},{x3,0}] 已知x>0,y>0 x3－y3＝x2－y2,求证 1 已知x>0,y>0 x3－y3＝x2－y2,求证 1