(1)(1-25%)x=72 (2)x-40%x=5.04 (3)x÷(1-40%)=3.6 (4) 34 x-25%x=12

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 16:32:04
(1)(1-25%)x=72(2)x-40%x=5.04(3)x÷(1-40%)=3.6(4)34x-25%x=12(1)(1-25%)x=72(2)x-40%x=5.04(3)x÷(1-40%)=3

(1)(1-25%)x=72 (2)x-40%x=5.04 (3)x÷(1-40%)=3.6 (4) 34 x-25%x=12
(1)(1-25%)x=72 (2)x-40%x=5.04 (3)x÷(1-40%)=3.6 (4) 34 x-25%x=12

(1)(1-25%)x=72 (2)x-40%x=5.04 (3)x÷(1-40%)=3.6 (4) 34 x-25%x=12
(1)(1-25%)x=72 (2)x-40%x=5.04
0.75x=72 0.6x=5.04
x=96 x=8.4
(3)x÷(1-40%)=3.6
x/0.6=3.6
x=2.16
(4) 34 x-25%x=12
33.75x=12
x=0.355

(1) (3/4)X=72 X=96
(2) 0.6X=5.04 X= 8.4
(3) (5/3)X=3.6 X=2.16
(4) 这个是不是弄错了,结果是12/33.75

3x²-(2x+5x-1),其中x=10 1/2x-(x+y/2x -x-y)÷(x+y) 化简:(x+3) / x^2-3x - x-1 / x^2-6x+9)除以x-9 / 3X-x^2怎么化? (1)x÷x=x x= (2)x2=2x x= (3(1)x÷x=x x=(2)x2=2x x=(3)x=x-x x= (x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25 化简:(2x/x-1)-(x/x+1)÷(x/x²-1) 求lim(x趋向于1)(x+x^2+x^3+...+x^n-n)/(x-1) 求lim(x趋向于1)(x+x^2+x^3+...+x^n-n)/(x-1) 已知f(x-1)=x²+4x-5则f(x)的表达式是() A x²+6x B x²+8x+7已知f(x-1)=x²+4x-5则f(x)的表达式是()A x²+6xB x²+8x+7C x²+2x-3D x²++6x-10 (x-1分之x²-x+1)÷1-x分之4x²-4x+1其中x满足x²+x-2=0 (1)(1-25%)x=72 (2)x-40%x=5.04 (3)x÷(1-40%)=3.6 (4) 34 x-25%x=12 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 x+60%x=80 80%-30x=305 35%x=210 x+50%x=60 x-40%x=0x+60%x=8080%-30x=30535%x=210x+50%x=60x-40%x=0.36(1-80%)x=21么么哒! 请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360 3x(x的2次方-x-1)(x+1)(3x-3)其中x=-1 求下列方程两根的和与积;x²-3x+2=105x²+x-5=0x²+x=5x+6(2x-1)²=(3-x)² 1.(1-x)/(x-2)=[1/(2-x)]-22.[(x-3)/(x²-1)]-[2/(1+x)] (x-1/3x-x+1/x)×x/x²-1 其中x=根号2-2 先化简