证明:2arctanX+arcsin(2X/(1+X^2))≡π,(X>=1)
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证明:2arctanX+arcsin(2X/(1+X^2))≡π,(X>=1)证明:2arctanX+arcsin(2X/(1+X^2))≡π,(X>=1)证明:2arctanX+arcsin(2X/
证明:2arctanX+arcsin(2X/(1+X^2))≡π,(X>=1)
证明:2arctanX+arcsin(2X/(1+X^2))≡π,(X>=1)
证明:2arctanX+arcsin(2X/(1+X^2))≡π,(X>=1)
解析:
令α=2arctanX,β=arcsin[2X/(1+X²)],其中0
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