若-cosx+sinx=根号2sin(x+α),则tanα为

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若-cosx+sinx=根号2sin(x+α),则tanα为若-cosx+sinx=根号2sin(x+α),则tanα为若-cosx+sinx=根号2sin(x+α),则tanα为解由sinx-cos

若-cosx+sinx=根号2sin(x+α),则tanα为
若-cosx+sinx=根号2sin(x+α),则tanα为

若-cosx+sinx=根号2sin(x+α),则tanα为
解由sinx-cosx=√2（√2/2sinx-√2/2cosx）=√2（cos45°sinx-sin45°cosx）
=√2sin（x-45°）=根号2sin(x+α),
即α=-45°
即tanα=tan（-45°）=-tan（45°）=-1

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