若-cosx+sinx=根号2sin(x+α),则tanα为
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若-cosx+sinx=根号2sin(x+α),则tanα为若-cosx+sinx=根号2sin(x+α),则tanα为若-cosx+sinx=根号2sin(x+α),则tanα为解由sinx-cos
若-cosx+sinx=根号2sin(x+α),则tanα为
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若-cosx+sinx=根号2sin(x+α),则tanα为
解由sinx-cosx=√2(√2/2sinx-√2/2cosx)=√2(cos45°sinx-sin45°cosx)
=√2sin(x-45°)=根号2sin(x+α),
即α=-45°
即tanα=tan(-45°)=-tan(45°)=-1
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