若x^2+3x-1=0,则x^3+5x^2+5x+8=
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若x^2+3x-1=0,则x^3+5x^2+5x+8=若x^2+3x-1=0,则x^3+5x^2+5x+8=若x^2+3x-1=0,则x^3+5x^2+5x+8=x²+3x=1所以原式=x&
若x^2+3x-1=0,则x^3+5x^2+5x+8=
若x^2+3x-1=0,则x^3+5x^2+5x+8=
若x^2+3x-1=0,则x^3+5x^2+5x+8=
x²+3x=1
所以原式=x³+3x²+2x²+6x-x+8
=x(x²+3x)+2(x²+3x)-x+8
=x+2-x+8
=10
x^3+5x^2+5x+8
=x*(x^2+3x-1)+2x^2+6x+8
=x*(x^2+3x-1)+2(x^2+3x-1)+2+8
=10
x^3+5x^2+5x+8
=(x^3+3x^2-x)+(2x^2+6x-2)+10
=x(x^2+3x-1)+2(x^2+3x-1)+10
=10
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
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