(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?

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(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?(cotα-1)/(2cotα+

(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?
(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?

(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?
(cotα-1)/(2cotα+1)=1
cotα-1=2cotα+1
cotα=-2
tanα=-1/2
所以
(cos2α)/(1+sin2α)
=(1-tan²α)/(1+tan²α)】/(1+2tanα/(1+tan²α))
=(1-tan²α)/(1+tan²α+2tanα)
=(1-tanα)/(1+tanα)
=(1+1/2)/(1-1/2)
=3