.1 ..Y = 1 + --------------- ..1 ..1+ ----------- ..1 ..1+ ------ ..x .小弟在这里谢过了!

方程y''=(1+y'*y')/2y的通解 微分方程y'-y=1 for(y=1;y y'=1+y^2 for (y=1;y y+y=1/cosx y'/y=1/x y(y-2)²-y(y+3)(y-5) y=1/2 化简求值 y(y-2)²-y(y+3)(y-5) y=1/2 化简求值 y(y-2)²-y(y+3)(y-5) y=1/2 化简求值 已知y=-2,求2y-2/y^2-2y+1+y+1/y-1-y的值 方程y''-4y'+13y=0的通解方程y''=(1+y'*y')/2y的通解 (y-2)(y^2-6y-9)-y(y^2-2y-15),其中y=1/2.先化简再求值. -y - y/1-y +1 [(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值. 解方程：3y^2-(2y+1)(y-1)=(y-5)(y+1) 解方程3y^2-(2y+1)(y-2)=(y-5)(y-1) 解方程：3y²-(2y+1)(y-2)=(y-5)(y+1)