y=4sin(x-π/4)cos(x+π/4)怎么化简啊!
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y=4sin(x-π/4)cos(x+π/4)怎么化简啊!y=4sin(x-π/4)cos(x+π/4)怎么化简啊!y=4sin(x-π/4)cos(x+π/4)怎么化简啊!y=4sin(x-π/4)
y=4sin(x-π/4)cos(x+π/4)怎么化简啊!
y=4sin(x-π/4)cos(x+π/4)怎么化简啊!
y=4sin(x-π/4)cos(x+π/4)怎么化简啊!
y=4sin(x-π/4)cos(x+π/4)
=4sin(x-π/4)sin[π/2-(x+π/4)] /后面一项运用余角公式
=4sin(x-π/4)sin(π/4 -x)
=-4sin²(x-π/4) /sin(-a)=-sina
=-2[1-cos(2x-π/2)] /运用二倍角公式：2sin²a=1-cos(2a)
=-2[1-cos(π/2 -2x)] /cos(-a)=cosa
=-2[1-sin(2x)]
=2sin(2x) -2
y=4sin(x-π/4)cos(x+π/4)
=4*2(cosx-sinx)(cosx-sinx)
=8(cosx-sinx)^2
=8(1-sin2x)
=8-8sin2x
y = 4sin(x - π/4)cos(x + π/4)
= 4sin(x - π/4)sin[π/2 - (x + π/4)]
= 4sin(x - π/4)sin(π/4 - x)
=-4[sin(x - π/4)]²
=-2(1 - cos(2x - π/2))
=2cos(π/2 - 2x) -2
=2sin2x -2
y=—4cos(x-兀/4+兀/2)cos(x+兀/4)=一4cos(x+兀/4)*cos(x+兀/4)=—2(cos(2x+兀/2)+1)=2sin2x—2。
函数y=sin(x)cos(x+ π/4)+cos(x)sin(x+π/4)的最小正周期是
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y=4sin(x-π/4)cos(x+π/4)怎么化简啊!
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