已知(x+y)(x+y-2)+6=30,求x+y的值.
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已知(x+y)(x+y-2)+6=30,求x+y的值.已知(x+y)(x+y-2)+6=30,求x+y的值.已知(x+y)(x+y-2)+6=30,求x+y的值.设:t=x+y则有:t(t-2)+6=
已知(x+y)(x+y-2)+6=30,求x+y的值.
已知(x+y)(x+y-2)+6=30,求x+y的值.
已知(x+y)(x+y-2)+6=30,求x+y的值.
设:t=x+y 则有:
t(t-2)+6=30
t^2-2t-24=0
(t-6)(t+4)=0
t=6 或 t=-4
所以:x+y=6 或x+y=-4
答案为6
令z=x+y
则
z(z-2)+6=30
z^2-2z+6-30=0
z^2-2z-24=0
(z-6)(z+4)=0
z=6或z=-4
所以x+y=6或-4
如有问题,可以追问。
谢谢您的采纳!
(x+y)²-2(x+y)-24=0
[(x+y)-6][(x+y)+4]=0
则:x+y=6或x+y=-4
6 -4
(X+Y)(X+Y-2)=24
X+Y=6
2*12=24
3*8=24
4*6=24
6-4=2
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