tan(arctan1/5+arctan3)
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tan(arctan1/5+arctan3)tan(arctan1/5+arctan3)tan(arctan1/5+arctan3)由tan(arctanx)=x可得原式=[tan(arctan1/5
tan(arctan1/5+arctan3)
tan(arctan1/5+arctan3)
tan(arctan1/5+arctan3)
由tan(arctanx)=x可得 原式=[tan(arctan1/5)+tan(arctan3)]/[1-tan(arctan1/5)tan(arctan3)]=8
tan(arctan1/5+arctan3)
tan(arctan1/5+arctan3)=
反三角函数2个问题,急求1:tan(arctan1/5+arctan3)2:cos【2arctan(3/4)】都是求值
tan (arctan1/5+arctan3)的值等于
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