若sinα=3/5(π/2
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若sinα=3/5(π/2若sinα=3/5(π/2若sinα=3/5(π/2因为sina=3/5且a在第二象限所以cosa=-4/5所以tana=-3/4tan(α-β)=(tana-tanβ)/1
若sinα=3/5(π/2
若sinα=3/5(π/2
若sinα=3/5(π/2
因为sina=3/5
且a在第二象限
所以cosa=-4/5
所以tana=-3/4
tan(α-β)
=(tana-tanβ)/1+tanatanβ
=(-3/4-1/2)/(1-3/8)
=-2
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