AB=AE,AC=AD,∠1=∠2.求证△ABC≌△AED
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AB=AE,AC=AD,∠1=∠2.求证△ABC≌△AEDAB=AE,AC=AD,∠1=∠2.求证△ABC≌△AEDAB=AE,AC=AD,∠1=∠2.求证△ABC≌△AED证明：∵∠1=∠2∴∠1+
AB=AE,AC=AD,∠1=∠2.求证△ABC≌△AED
AB=AE,AC=AD,∠1=∠2.求证△ABC≌△AED
AB=AE,AC=AD,∠1=∠2.求证△ABC≌△AED
证明：
∵∠1=∠2
∴∠1+∠DAC=∠2+∠DAC
即∠BAC=∠EAD
又AB=AE,AC=AD
∴△ABC≌△AED （SAS）
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