x/2=y/3=z/4,5x+2y-3z=8
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x/2=y/3=z/4,5x+2y-3z=8x/2=y/3=z/4,5x+2y-3z=8x/2=y/3=z/4,5x+2y-3z=8设x/2=y/3=z/4=k∴x=2k,y=3k,z=4k设一个中间
x/2=y/3=z/4,5x+2y-3z=8
x/2=y/3=z/4,5x+2y-3z=8
x/2=y/3=z/4,5x+2y-3z=8
设x/2=y/3=z/4=k
∴x=2k,y=3k,z=4k 设一个中间变量k,方便解决问题
把x=2k,y=3k,z=4k 代入5x+2y-3z=8得
∴10k+6k-12k=8
4k=8
k=2
把k=2代入x=2k,y=3k,z=4k得
x=4
y=6
z=8
x/2=y/3=z/4
y=3/2x
z=2x
5x+2y-3z=8
5x+2*3/2x-3*2x=2x=8
x=4
y=3/2x=4*3/2=6
z=2x=2*4=8
收起 x/2=y/3=z/4, 可设 x y z 分别为 2k 3k 4k
5x+2y-3z=8 = 10k+6k-12k = 4k
k=2
x= 4 y= 6 z=8
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
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x+y=5 2x+3y-z=9 x-y+z=4
2x+z=10 x+y-z=4 3x-y-z=0
已知:4x-5y+2z=0 x+4y-3z=0则:(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x+y+z=4 2x-y+z=3 3x-2y-3z=-5
{ 5x-3y+z=25x+2y-4z=3-5x+y-z=2
x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=?
3x-2y+z=4 x+y-z=5 4x-4y+3z=27
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快