｛ 5x-3y+z=25x+2y-4z=3-5x+y-z=2

｛ 5x-3y+z=25x+2y-4z=3-5x+y-z=2 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? x/2=y/3=z/5 x+3y-z/x-3y+z x+y/2=z+x/3=y+z/4 x+y+z=27 x+2y=3x+2z=4y+z 求x:y:z 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x+y=5 2x+3y-z=9 x-y+z=4 六年级三元一次方程组.解下列方程组：(1)5x-3y+z=25x+2y-4z=3-5x+y-z=2(2)x-y-z=-13x_5y+7z=114x-y+2z=-1(3)9x-5y+z=-69x+y+4z=3-9x+3y-5z=0(4)x+y=22x+z=-27y+z=13 1.5x-3y+z=25x+2y-4z=3-5y+y-z=2以上是第一题.2.x+y=-2x+z=13y+z=1以上是第二题.3.x-y-z=-13x+5y+7z=114x-y+2z=-1以上是第三题. 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. 解下列方程 三元一次方程一、 5x-3y+z=25x+2y-4z=3-5x+y-z=2二、x+y=-2x+z=13y+z=1三、x-y-z=-13x+5y+7z=114x-y+2z=-1第二题不用了 已知：4x-5y+2z=0 x+4y-3z=0则：(x*x+y*y+z*z)/(x*y+y*z+z*x)=____. 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 4x-y+z=25,6x-z+2y=22,x+3y+z=-2 {4x-y+z=25,6x-z+2y=22,x+3y+z=-2 蟹蟹 3x-2y+z=4 x+y-z=5 4x-4y+3z=27