x+y+Z=50 1500x+2100y+2500z=90000
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x+y+Z=501500x+2100y+2500z=90000x+y+Z=501500x+2100y+2500z=90000x+y+Z=501500x+2100y+2500z=90000三个未知数,两
x+y+Z=50 1500x+2100y+2500z=90000
x+y+Z=50 1500x+2100y+2500z=90000
x+y+Z=50 1500x+2100y+2500z=90000
三个未知数,两个方程,神也解答不出来啊
方程组{x+y+z=50,1500x+2100y+2500z方程组是{x+y+z=50,1500x+2100y+2500z=90000
三元一次方程组 1500x+2100y+2500z=90000 x+y+z=50
x+y+Z=50 1500x+2100y+2500z=90000
(x+y-z)(x-y+z)=
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值
z+=x>y?++x:
x=y; y=z; z=x/y
解方程 Y=X+Z Y-Z=2 100Z+10Y+X-(100X+10Y+Z)=99 Y=X+ZY-Z=2100Z+10Y+X-(100X+10Y+Z)=99
解三元一次方程组x+y=50-z 1500x+2100y=90000-2500z
求{X+Y+Z=50 {1500X+2100Y+2500Z=90000 方程组的正整数解
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
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已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
fangchengzu:X+Z=Y 7Z=X+Y+Z X+Y+Z=14
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