数列an满足a(n-1)-an=1/2,a1=1/2,sn是数列an的前n项和,则S100=?
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数列an满足a(n-1)-an=1/2,a1=1/2,sn是数列an的前n项和,则S100=?数列an满足a(n-1)-an=1/2,a1=1/2,sn是数列an的前n项和,则S100=?数列an满足
数列an满足a(n-1)-an=1/2,a1=1/2,sn是数列an的前n项和,则S100=?
数列an满足a(n-1)-an=1/2,a1=1/2,sn是数列an的前n项和,则S100=?
数列an满足a(n-1)-an=1/2,a1=1/2,sn是数列an的前n项和,则S100=?
an-a(n-1)=-1/2
所以等差,d=-1/2
a1=1/2
所以an=-n/2+1
所以S100=(a1+a100)*100/2=-2425
a(n-1)-an=1/2
所以
d=an-a(n-1)=-1/2
a100=a1+(100-1)d=1/2-99/2=-49
所以
s100=(a1+a100)×100÷2=(1/2-49)×50=-2425
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