设u=(e^xy)(cos(x+y^2)),求du
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设u=(e^xy)(cos(x+y^2)),求du设u=(e^xy)(cos(x+y^2)),求du设u=(e^xy)(cos(x+y^2)),求du对x偏导du/dx=ye^xy(cos(x+y^2
设u=(e^xy)(cos(x+y^2)),求du
设u=(e^xy)(cos(x+y^2)),求du
设u=(e^xy)(cos(x+y^2)),求du
对x偏导du/dx=ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2)) 偏导的那个a打不出来
对y偏导du/dy=xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y
du={ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2))}dx+{xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y}dy 里面的小项没有整理...
du={e^(xy)[ycos(x+y^2)-sin(x+y^2)]}dx+
{e^(xy)[xcos(x+y^2)-2ysin(x+y^2)]}dy
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设函数y=f(x)由方程e^(2x+y)+cos(xy)=e-1所确定,则dy=_____设函数y=f(x)由方程e^(2x+y)-cos(xy)=e-1所确定,则dy=_____。上面的写错啦。
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y=cos^2(x^2-x)求导,要设u= v=那种
yˊ=1/xy*[sin(xy^2)]^2-y/2x答案是设u=xy^2 ,最后结果是uˊ=2/(sinu)^2
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设f(u,v)是可微分函数且z=f(2x+3y,e^xy),则dz=
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