设u=cosh(xy)+cos(xy),则du=

设u=cosh(xy)+cos(xy),则du= 设u=(e^xy)(cos(x+y^2)),求du 设u={cos(x^2)}/y +(xy)^(y/x) 求du 关于复合函数求导设u=xy,u`=y+xy` 设Z=e^xy COS(xy),求dz|(0,1) yˊ=1/xy*[sin(xy^2)]^2-y/2x答案是设u=xy^2 ,最后结果是uˊ=2/(sinu)^2 设u=f( lnxy ,sin(xy) ),求x和y关于u的偏导数 设xy 设函数u=f(xy,x/y),求:偏u/偏x,偏u/偏y?$(acontent) u=xy^2+arctan(xy) 求du 设z=uv,u=e^(x+y),v=ln(xy)求dy 设u=xy( x> 0,x≠1),则du= 设u=f(x,xy,xyz)的一阶偏导数 设f(x,y)=xy+f(u,v)dudv,如题, z=sin(xy)+cos^2(xy)一阶偏导数 z=sin(xy)+cos^2(xy)一阶偏微分 设z=u^2cosv^2,u=x+y,v=xy,求dz/dx,dz/dy.高数题 设e^(x+y)+cos(xy)=0确定y是x的函数求dy