解数学M^2-M-1=0,M^5-5M-3=?
来源：学生作业帮助网 编辑：六六作业网 时间：2025/01/19 19:15:43
解数学M^2-M-1=0,M^5-5M-3=?解数学M^2-M-1=0,M^5-5M-3=?解数学M^2-M-1=0,M^5-5M-3=?M^5-5M-3=M^3(M^2-M-1)+M^4+M^3-5
解数学M^2-M-1=0,M^5-5M-3=?
解数学M^2-M-1=0,M^5-5M-3=?
解数学M^2-M-1=0,M^5-5M-3=?
M^5-5M-3
=M^3(M^2-M-1)+M^4+M^3-5M-3
=M^2(M^2-M-1)+2M^3+M^2-5M-3
=2M(M^2-M-1)+3M^2-3M-3
=3(M^2-M-1)
=0
很高兴为您解答,【the 1990】团队为您答题.
请点击下面的【选为满意回答】按钮.
解数学M^2-M-1=0,M^5-5M-3=?
m*m-5m-1=0则2m*m-5m+1/m*m
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
m-2m-3m+4m-5m-6m+7m.2004m=?
(m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=?
已知m*m+m-1=0,求m*m*m+2m*m-2005
已知m^2-5m+1=0,求m^3+1/m^3 和m-1/m的值
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
当m=1/2时,求15m²-9-{-4m²+[5m-8m²-(2m²-m)+9m²]-3m}
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
当m= 时,2m(3m-5)+3m(1-2m)=14
已知m^2-5m-1=0,求(m^4+1)/m^2的值
化简|6-m|-|2m+1|+|m+5| (m
已知2m-5n=0,求（1+n/m-m/m-n）/(1-n/m-m/m+n)的值
已知2m-5n=0,求值:(1+n/m-m/m-n)÷(1-n/m-m/m+n)
已知2m-5n=0,求(1+m分之n-m-n分之m)/(1-m分之n-m+n分之m)的值
已知2m-5n=0,求值:(1+n/m-m/m-n)÷(1-n/m-m/m+n)急
已知m²-5m-1=0,求2m²-5m+m²／1=?已知m²-5m-1=0,求2m²-5m+1／m²=？