求值(log2 5+log4 1/5)(log5 2+log25 1/2)

求值(log2 5+log4 1/5)(log5 2+log25 1/2) 求值：3^(log3 (25) )+(-C(5,4)^(log2 1)+16^(log4(2sin(π/2))= 解方程：log2(3-x) - log4(x+5) =1 log2(x-2)=log4(5-x) 计算：log2(8)×log4(5)×log5(16) log2 20---log2 5+log3 4 * log4 3 等于什么 log2(20)-log2(5)+2log3(2)×log4(3) 求值：【log2（3）+log4（9）+log8（27）+log16（81）+log32（243）】—5log2（3/2) log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证 高中数学对数计算求值（log2 125+log4 25+log8 5）*（log125 8+log25 4+log5 2）要用简便运算啊. 方程log2(X+1)^2+log4(X+1)=5的解是.. 方程log2(x+1)^2+log4(x+1)=5的解是 log2（X+1）的平方+log4（X+1)的平方=5的解 log2 (x+1)^2 +log4 (x+1)=5的解是( ) (log2 5+log4 125)log3 2/ log根号3 5 求(log2 5+log4 0.2)(log5 2+log25 0.5) log2(3),log4(5),3/2怎么比较大小? (log2^5+log4^0.2)(log5^2+log25^0.25)化简