2012x=1+2+3+4+5.

一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X x/1*2+x/2*3+x/3*4+x/4*5.+x/2012*2013=2012 解方程. 1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.1/(x+2011)(x+2012)=1/2x+4024 (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 已知：x^2+x-1=0,那么x^4+2x^3-x^2-2x+2012=? (x+1)(x+2)(x+3)(x+4)=24 (x-1)(x-2)(x-3)(x-4)=48 (x+1)(x+2)(x+3)(x+4)=24 x-1+x+2+x/3+4x=77 一道分式方程.X-2分之X-1减X-3分之X-2=X-5分之X-4减X-6分之X-5.要具体. 解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4 x*2-4x+4/(x*-9)]/[x*-4/(x*2+3x)]/(1/3)x 其中x=-1