log2 1+ log2 2+ … + log2 n >= ⌊n/2」log2 (n/2) 求证明,2是底

log2 1+ log2 2+ … + log2 n >= ⌊n/2」log2 (n/2) 求证明,2是底 log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 |[log2(x)]^2-3log2(x)+1| (log2)2+log2*log50+1g25值 log2(2X-1) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32 计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2(log2 16)（以2为底的…） log2 (2^x-1)·log2 [2^(x+1)-2] log2 (2^x-1)·log2 [2^(x+1)-2] log2(x-1)>2定义域log2(x-1)>2 定义域 解方程log2(2-x)=log2(x-1)+1 解2log2^(x-5)=log2^(x-1)+1 2^log2 (3) × log2 (1/8) + 2lg3