已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立,求A和B

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已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立,求A和B已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立,求A和B已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立

已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立,求A和B
已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立,求A和B

已知4/(x^2-1)=A/(x-1)+B/(x+1)恒成立,求A和B
4/(X^2-1)
=4/[(X-1)(X+1)]
=2/(X-1)-2/(X+1)
=A/(X-1)+B/(X+1)
经比较得:
A=2 B=-2
可以给分否?