若lim(2n-√4n^2+an+3)=1,n→∞,求a.

若lim (3n^2+5)An=2,且lim （1-n^2）An? 若lim(2n-√4n^2+an+3)=1,n→∞,求a. 若lim[(2n-1)an]=1 求lim(n*an)的值 已知liman=2求lim((n+an)/(n-an)) lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b 在数列{an}中,a1=2,且an=1/2(a[n-1]+3/a[n-1]),(n>=2),若lim(n→∞）an存在,则lim(n→∞)an=? lim 2n-根号(3-an+4n^2)=1,则a为 若lim(an^2+2n+3)/(an^2-3n+4)=1/b,求ab的值n不是下标, 数列极限的运算lim an/(an+1) =2 求lim 2anlim (2n+1)*an=3 求lim n*an lim[(4+7+...+3n+1)/(n^2-n)]= lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?（n趋近于无穷大）为什么不成立? 若极限lim((3n^2+4)/(n+2)-an+b)=6,则a=_,b=_ lim(n趋于无穷大)(5n^2+3n)/(an^2+b)=多少 数列极限（已知lim[（2n-1）an]=2,求lim n*an） lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5求常数a、b、c lim(n+3)(4-n)/(n-1)(3-2n) lim(n^3+n)/(n^4-3n^2+1) lim(n→无限大）An=1+1/3lim(n→无限大）*(1+4/9+(4/9)^2...+(4/9)^(n-2))