∫x^2(√4-x^2)dx

∫{√（x^4+x^-4+2)}/x^3dx 求教不定积分∫x √（4x-x^2)dx ∫ x/√(x^2+4x+5)dx 求不定积分 ∫ 1/(1+2x)² dx ∫ x/√x²+4 dx ∫√(4-x^2)dx等于? ∫√(4-x^2)dx ∫X√(2-5X)dx ∫(√(x^2+6x))dx ∫x√(1+2x)dx ∫（x^2+1/x^4)dx ∫dx/根号(4x-x^2) ∫1/(x^4-x^2)dx ∫x/(4+9x^2)dx 求∫x-3/x²-2x+2 dx,∫x³/√（4-x²）dx ∫(x-2)√（4-x^2）dx ∫x^2(√4-x^2)dx ∫[-1,1](x+√4-x^2)^2dx ∫(1-x)/[√(9-4x^2)]dx=