∫x/(4+9x^2)dx
来源：学生作业帮助网 编辑：六六作业网 时间：2025/02/02 14:42:42
∫x/(4+9x^2)dx∫x/(4+9x^2)dx∫x/(4+9x^2)dx∫x/(4+9x^2)dx=1/2*∫dx^2/(4+9x^2)=1/18*∫d9x^2/(4+9x^2)=1/18*∫d
∫x/(4+9x^2)dx
∫x/(4+9x^2)dx
∫x/(4+9x^2)dx
∫x/(4+9x^2)dx
=1/2*∫dx^2/(4+9x^2)
=1/18*∫d9x^2/(4+9x^2)
=1/18*∫d(9x^2+4)/(4+9x^2)
=1/18*ln(9x^2+4)+c
=1/18 1/(4+9x^2) d(4+9x^2) = 1/18 ln(4+9x^1)
∫x/(4+9x^2)dx
用换元法求 ∫dx/(4-9x^2)
∫dx／根号4-9x^2
积分符号∫ 2^x/(1+4^x) dx积分符号∫(X+1)/(x^2+9) dx积分符号∫(tg根号X) / 根号X dx
∫x^3/9+X^2 dx.
∫3+x/(9-x^2)dx
∫x^3/(9+x^2)dx
∫（x^2+1/x^4)dx
∫dx/根号(4x-x^2)
∫1/(x^4-x^2)dx
∫x^2/(9+4x^2)dx
∫x^2/(4+9x^2)dx求高手
∫(1-x)/[√(9-4x^2)]dx=
∫1-x/(√9-4x^2)dx,
求∫ (x-1)/ （9-4x^2）dx
∫(x-1)/√(9-4x^2)dx不定积分
求不定积分∫x/(√4-9x^2)dx
∫1/(9x^2+12x+4)dx