1.25x(0.8+0.4)x2.5能用简便么?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 04:00:31
1.25x(0.8+0.4)x2.5能用简便么?1.25x(0.8+0.4)x2.5能用简便么?1.25x(0.8+0.4)x2.5能用简便么?1.25x(0.8+0.4)x2.5=1.25x2.5x
1.25x(0.8+0.4)x2.5能用简便么?
1.25x(0.8+0.4)x2.5能用简便么?
1.25x(0.8+0.4)x2.5能用简便么?
1.25x(0.8+0.4)x2.5
=1.25x2.5x0.8+1.25x2.5x0.4
=1x2.5+1.25x1
=2.5+1.25
=3.75
先算后式再算前式
(0.8*2.5+0.4*2.5)=3
3*1.25=3.75
答案是3.75
1.25x(0.8+0.4)x2.5
=1.25*0.8*2.5+1.25*0.4*2.5
=1*2.5+1*1.25
=3.75
是这样吗
可以简便计算:
1.25x(0.8+0.4)x2.5
=(1.25x0.8+1.25x0.4)x2.5
=(1+1.25x0.4)x2.5
=1x2.5+1.25x0.4x2.5
=2.5+1.25x1
=2.5+1.25
=3.75
【不懂欢迎追问,有帮助请采纳】
1.25x(0.8+0.4)x2.5能用简便么?
y=x2/(x-1)的值域最好能用判别式
5(x2-x)=3(x2+x)
0.4x-8.5 x2
x2-5x+6
x2-5x+6
x2-5x+8
3x2+5x
f(x-(1/x))=x2+(1/x2)则f(x-1)=2为平方 能用换元法么
不等式(x2-4x-5)(x2-8)
x2-1/x2-5x+6
(1-x2)(x2-4x+5)
不等式(x2-4x-5)(x2+1)
x2-5x+1=0则x2+x2/1
判定函数f(x)=x+(根号下(x2+1))单调性能用x1 x2相减来做么?
5x2—[x2+(4x—x2)—2(x2—3x)]
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
(x2+5x-4)(x2+5x+6)-120 因式分解